"A thing of beauty is a joy forever..."
It's loveliness increases, it will never
Pass into nothingness..." Keats, Endymion
You study the lines of these 25 to 35 footers clamped in their stands. The poor Columbia really wasn't as cute as the Ariel, not as well proportioned as an H-28, I'm sure.
Somehow you hope the attractive ones are favored and will go on forever giving an eyeful of joy - and give the skipper a magic transcendence from the gloom bekoning on the shore.
I can see it may have been better to be attacked by marina sharks and crunched by orcas than to pass passive and wounded into nothingness for lack of a bit of love and attention.
A pretty boat is as good an invention of the human spirit we'll ever have. It is a weird excess to abandon a boat. You won't get a seat in that big clam shack in the sky for that insult. And I'm thinking I'll not be happy with those jam cleats off a damned unlucky little ship.
Remind them of bone yard boats!
For those that don't know, there is a newsletter (and web site) that offers the boat yard a chance to get a few $$ back, and save a great old boat. http://www.by-the-sea.com/ has the on-line version of the long running newsletter. If you see an old Bone Yard Boats.
And if you are looking for a classic boat for nearly nothing (and sometimes free), consider rescuing one for your self. I hope to do that when I get to retirement age.
A/C prismatic coefficient
- but certainly the weight of a boat is its displacement. Boat displaces a volume of water whose weight is the same as the boat's.
Well, I did as I suggested because I knew none of you really cared what the Cp is. You rotters. Me neither, but I again woke in the middle of the night and had to do something about it. I traced the underwater athwartship portion, cut it up, pasted it onto 1" squares, came up with 8.25 square feet.
5280 (displacement) divided by 64 = 82.5 cu ft (volume of displacement)
8.25 (area of displacement in maximum cross section) times the waterline = a 'prismatic' shaped volume
which is divided into the actual volume of displacement.
The answer is .54
You will visualize the prismatic displacement if you take the maximum beam mid section at the waterline and place it at both ends of the waterline, at the bow and under the stern. It's a rectangular shape that has the same three-dimensional shape of the midsection from bow to stern. It is a volume that is only real to create the Cp. number.
Imagine a large pingpong ball. When put in the water it sinks in 1 foot and has an 18.5 foot waterline. Float another sphere of different material, it sinks in 2 feet and has an 18.5 foot waterline. Now float a third sphere that has a different diameter and floats at 3.5 feet with an 18.5 foot waterline. The prismatical shape of the spheres would all be squares (on the water surface with a U-shaped quanset hut roof like volume going from one end of the waterline to the other. Each sphere has a different displacement and a different prismatic volume. Guess which sphere will push thru the water easiest. Corse I could have toll you without all this rigamarol, It's the first and biggest sphere. It would have the smallest Cp value. [What would be the athwartsphere area at the WL of the third and smallest sphere - how like or unlike the Ariel? shape doesn't matter!]
But there is something strange here. I got more square area the second time (8.25 vs 7) and I guarantee it's pretty accurate, why did the larger area generate a smaller Cp? Supposedly, the further away from 1 the faster the boat. ???
I've had some dealings with a N.A. recently. Maybe I'll ask him. This is it for me on this eye glazer. .54 Cp sounds pretty good to me for a sailboat that has half of it's weight in lead! And any of this high-fallutin math have a form ula for the ingredible sexy underwater shape of these boats? Whatever.
As the prince said to Cinderella, "Hope the shoe fits!"